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.01x^2-2.7x+182=0
a = .01; b = -2.7; c = +182;
Δ = b2-4ac
Δ = -2.72-4·.01·182
Δ = 0.010000000000001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.7)-\sqrt{0.010000000000001}}{2*.01}=\frac{2.7-\sqrt{0.010000000000001}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.7)+\sqrt{0.010000000000001}}{2*.01}=\frac{2.7+\sqrt{0.010000000000001}}{0.02} $
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